I have scripts calling other script files but I need to get the filepath of the file that is currently running within the process.
For example, let's say I have three files. Using execfile:
script_1.py calls script_2.py. script_2.py calls script_3.py. How can I get the file name and path of script_3.py, from code within script_3.py, without having to pass that information as arguments from script_2.py?
(Executing os.getcwd() returns the original starting script's filepath not the current file's.)